
Question:
I was wondering if it were possible to include variables when using expression
in R.
For instance I would like to do something like this:
par(mfrow=c(2,3)) for (i in 1:6) { plot(x, p1-i*p2, main=expression(Phi[1] - i * Phi[2])) }
But this does not work, as it prints Φ1 - iΦ2 (i.e. it does not substitute i
with 1, 2, ... 6
Solution:1
Use substitute:
> substitute(Phi[1] - i* Phi[2], list(i = i)) Phi[1] - 3 * Phi[2]
Solution:2
Looks like it uses the variables. I set x = 1 and used the following.
> p1 = 100 > p2 = 10 > for (i in 1:6) + { + plot(x, p1-i*p2, main=expression(Phi[1] - i * Phi[2])) + } >
It gave me 6 graphs for Φ1 - iΦ2 with each showing the Y value descending.
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