# Tutorial :Convert ASCII string into Decimal and Hexadecimal Representations ### Question:

I need to convert an ASCII string like... "hello2" into it's decimal and or hexadecimal representation (a numeric form, the specific kind is irrelevant). So, "hello" would be : 68 65 6c 6c 6f 32 in HEX. How do I do this in C++ without just using a giant if statement?

EDIT: Okay so this is the solution I went with:

``int main()  {      string c = "B";      char *cs = new char[c.size() + 1];      std::strcpy ( cs, c.c_str() );      cout << cs << endl;        char a = *cs;      int as = a;      cout << as << endl;      return 0;  }  ``

### Solution:1

You can use printf() to write the result to stdout or you could use sprintf / snprintf to write the result to a string. The key here is the %X in the format string.

``#include <cstdio>  #include <cstring>  int main(int argc, char **argv)  {      char *string = "hello2";      int i;        for (i = 0; i < strlen(string); i++)          printf("%X", string[i]);        return 0;  }  ``

If dealing with a C++ std::string, you could use the string's c_str() method to yield a C character array.

### Solution:2

Just print it out in hex, something like:

``for (int i=0; i<your_string.size(); i++)      std::cout << std::hex << (unsigned int)your_string[i] << " ";  ``

Chances are you'll want to set the precision and width to always give 2 digits and such, but the general idea remains the same. Personally, if I were doing it I'd probably use `printf("%.2x");`, as it does the right thing with considerably less hassle.

### Solution:3

A string is just an array of `char`s, so all you need to do is loop from `0` to `strlen(str)-1`, and use `printf()` or something similar to format each character as decimal/hexadecimal.

### Solution:4

``#include <algorithm>  #include <iomanip>  #include <iostream>  #include <iterator>    int main() {    std::string hello = "Hello, world!";      std::cout << std::hex << std::setw(2) << std::setfill('0');    std::copy(hello.begin(),              hello.end  (),              std::ostream_iterator<unsigned>(std::cout, " "));    std::cout << std::endl;  }  ``

### Solution:5

``for(int i = 0; i < string.size(); i++) {      std::cout << std::hex << (unsigned int)string[i];  }  ``

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