
Question:
Is there any way to do code such this:
class GenericClass<T> { void functionA() { T.A(); } }
Or, how to call a function of type parameter (type is some my custom class).
Solution:1
To call a method of a generic type object you have to instantiate it first.
public static void RunSnippet() { var c = new GenericClass<SomeType>(); } public class GenericClass<T> where T : SomeType, new() { public GenericClass(){ (new T()).functionA(); } } public class SomeType { public void functionA() { //do something here Console.WriteLine("I wrote this"); } }
Solution:2
Re:
T.A();
You can't call static methods of the type-parameter, if that is what you mean. You would do better to refactor that as an instance method of T
, perhaps with a generic constraint (where T : SomeTypeOrInterface
, with SomeTypeOrInterface
defining A()
). Another alternative is dynamic
, which allows duck-typing of instance methods (via signature).
If you mean that the T
is only known at runtime (as a Type
), then you would need:
typeof(GenericClass<>).MakeGenericType(type).GetMethod(...).Invoke(...);
Solution:3
I think you are looking for generic type constraints:
class GenericClass<T> where T : MyBaseClass { void functionA<T>(T something) { something.A(); } }
In terms of the code you posted - in order to call something on T
, you will need to pass it as a parameter to functionA
. The constraint you use will have to ensure that any T
has an A
method that can be used.
Solution:4
I understand from your code that you want to call a type parameter static method, and that's just impossible.
See here for more info : Calling a static method on a generic type parameter
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