Question:
String messageFile = ... // Assume messageFile SHOULD have the string "MESSAGE" System.out.println("The messageFile is: " + messageFile + "!!"); Normally, one would expect the above command to output:
The messageFile is: MESSAGE!!!! However, I am receiving this instead:
!!e messageFile is: MESSAGE See how the above statement, the "!!" points seem to wrap around the message. My theory is that the:
String messageFile = ... contains more characters than my assumed "MESSAGE". As a result, it's wrapping the next input (in this case, the "!!") to the front of the System.out.println() message.
What character is causing this?
Extra info:
Btw, messageFile is being initialized by passing a command line argument to a java class, myClassA. myClassA's constructor uses a super() to pass the messageFile parameter to myClassB. myClassB passes messageFile into a function().
Solution:1
I would guess you have a stray carriage return (\r) within the messageFile variable that is unaccompanied by a line feed (\n).
EDIT - this tests as expected:
class Println { public static void main(String[] args) { System.out.println("xxxx this \rTEST"); } } Output:
TEST this
Solution:2
Your message variable possibly contains a '\r' (carriage return) or '\n' (line feed) character at the end. This may cause the cursor to return to the first column before printing the exclamation marks.
Solution:3
For debugging you should print the codepoint of each character of messageFile via codePointAt. As as result you see exactly the content of messageFile.
Solution:4
Replace all carriage returns in the file with newlines and then replace all double-newlines with single-newlines:
messageFile.replace('\r', '\n').replace("\n\n", "\n) Carriage returns should be banned :D
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