Question:
I have written following regular expression /^[A-Za-z0-9-_\s]*$/ in PHP which allows numbers, letters, spaces, hyphen and underscore. I want to display those matches which are not valid against the regex i.e "My Name is Blahblah!!!" should give me "!!!" output.
Solution:1
Use the caret symbol inside the character class to invert the match and remove the start (^) and end ($) characters:
/[^A-Za-z0-9-_\s]+/ http://php-regex.blogspot.com/2008/01/how-to-negate-character-class.html
Solution:2
If you replace all the matches with the empty string then you'll get the non-matching parts back:
preg_replace('/[A-Za-z0-9-_\s]+/', '', $string) This will work for any arbitrary regex, but for your specific regex @Andy's solution is simpler.
Notice that I removed the anchors ^ and $ to make this work.
Solution:3
preg_replace("/^[A-Za-z0-9-_\s]*$/","","My Name is Blahblah!!!") // Output: "!!!"
Or, if you want all the groupings of them
preg_split("/^[A-Za-z0-9-_\s]*$/","","My Name is Blahblah!!!")
Solution:4
You have to put the hiphen - at the begining or at the end of the character class or escape it, so your regex would be :
/[^-A-Za-z0-9_\s]+/ or
/[^A-Za-z0-9_\s-]+/ or
/[^A-Za-z0-9\-_\s]+/ Note:If u also have question or solution just comment us below or mail us on toontricks1994@gmail.com
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