Tutorial :How to determine if a decimal/double is an integer?



Question:

How do I tell if a decimal or double value is an integer?

For example:

decimal d = 5.0; // Would be true  decimal f = 5.5; // Would be false  

or

double d = 5.0; // Would be true  double f = 5.5; // Would be false  

The reason I would like to know this is so that I can determine programmatically if I want to output the value using .ToString("N0") or .ToString("N2"). If there is no decimal point value, then I don't want to show that.


Solution:1

For floating point numbers, n % 1 == 0 is typically the way to check if there is anything past the decimal point.

public static void Main (string[] args)  {      decimal d = 3.1M;      Console.WriteLine((d % 1) == 0);      d = 3.0M;      Console.WriteLine((d % 1) == 0);  }  

Output:

False  True  

Update: As @Adrian Lopez mentioned below, comparison with a small value epsilon will discard floating-point computation mis-calculations. Since the question is about double values, below will be a more floating-point calculation proof answer:

Math.Abs(d % 1) <= (Double.Epsilon * 100)  


Solution:2

There are any number of ways to do this. For example:

double d = 5.0;  bool isInt = d == (int)d;  

You can also use modulo.

double d = 5.0;  bool isInt = d % 1 == 0;  


Solution:3

How about this?

public static bool IsInteger(double number) {      return number == Math.Truncate(number);  }  

Same code for decimal.

Mark Byers made a good point, actually: this may not be what you really want. If what you really care about is whether a number rounded to the nearest two decimal places is an integer, you could do this instead:

public static bool IsNearlyInteger(double number) {      return Math.Round(number, 2) == Math.Round(number);  }  


Solution:4

Whilst the solutions proposed appear to work for simple examples, doing this in general is a bad idea. A number might not be exactly an integer but when you try to format it, it's close enough to an integer that you get 1.000000. This can happen if you do a calculation that in theory should give exactly 1, but in practice gives a number very close to but not exactly equal to one due to rounding errors.

Instead, format it first and if your string ends in a period followed by zeros then strip them. There are also some formats that you can use that strip trailing zeros automatically. This might be good enough for your purpose.

double d = 1.0002;  Console.WriteLine(d.ToString("0.##"));  d = 1.02;  Console.WriteLine(d.ToString("0.##"));  

Output:

1  1.02  


Solution:5

bool IsInteger(double num) {      if (ceil(num) == num && floor(num) == num)          return true;      else          return false;  }  

Problemo solvo.

Edit: Pwned by Mark Rushakoff.


Solution:6

If upper and lower bound of Int32 matters:

public bool IsInt32(double value)  {      return  value >= int.MinValue && value <= int.MaxValue && value == (int)value;  }  


Solution:7

static bool IsWholeNumber(double x)   {      return Math.Abs(x % 1) < double.Epsilon;  }  


Solution:8

Mark Rushakoff's answer may be simpler, but the following also work and may be more efficient since there is no implicit division operation:

     bool isInteger = (double)((int)f) == f ;  

and

     bool isInteger = (decimal)((int)d) == d ;  

If you want a single expression for both types, perhaps

     bool isInteger = (double)((int)val) == (double)val ;  


Solution:9

You can use String formatting for the double type. Here is an example:

double val = 58.6547;  String.Format("{0:0.##}", val);        //Output: "58.65"    double val = 58.6;  String.Format("{0:0.##}", val);        //Output: "58.6"    double val = 58.0;  String.Format("{0:0.##}", val);        //Output: "58"  

Let me know if this doesn't help.


Solution:10

    public static bool isInteger(decimal n)      {          return n - (Int64)n == 0;      }  


Solution:11

I faced a similar situation, but where the value is a string. The user types in a value that's supposed to be a dollar amount, so I want to validate that it's numeric and has at most two decimal places.

Here's my code to return true if the string "s" represents a numeric with at most two decimal places, and false otherwise. It avoids any problems that would result from the imprecision of floating-point values.

try  {      // must be numeric value      double d = double.Parse(s);      // max of two decimal places      if (s.IndexOf(".") >= 0)      {          if (s.Length > s.IndexOf(".") + 3)              return false;      }      return true;  catch  {      return false;  }  

I discuss this in more detail at http://progblog10.blogspot.com/2011/04/determining-whether-numeric-value-has.html.


Solution:12

Using int.TryParse will yield these results: var shouldBeInt = 3;

        var shouldntBeInt = 3.1415;            var iDontWantThisToBeInt = 3.000f;            Console.WriteLine(int.TryParse(shouldBeInt.ToString(), out int parser)); // true            Console.WriteLine(int.TryParse(shouldntBeInt.ToString(), out parser)); // false            Console.WriteLine(int.TryParse(iDontWantThisToBeInt.ToString(), out parser)); // true, even if I don't want this to be int            Console.WriteLine(int.TryParse("3.1415", out  parser)); // false            Console.WriteLine(int.TryParse("3.0000", out parser)); // false            Console.WriteLine(int.TryParse("3", out parser)); // true            Console.ReadKey();  


Solution:13

Perhaps not the most elegant solution but it works if you are not too picky!

bool IsInteger(double num) {      return !num.ToString("0.################").Contains(".");  }  


Solution:14

You could use the 'TryParse' method.

int.TryParse()  

This checks to see if the value can be converted to an integer whole number value. The result can then indicate a flag which can be used elsewhere in your code.


Solution:15

Try this:

number == Convert.ToInt16(number);  

Note:If u also have question or solution just comment us below or mail us on toontricks1994@gmail.com
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