# Tutorial :Why does x,y = zip(*zip(a,b)) work in Python?

### Question:

OK I love Python's `zip()` function. Use it all the time, it's brilliant. Every now and again I want to do the opposite of `zip()`, think "I used to know how to do that", then google python unzip, then remember that one uses this magical `*` to unzip a zipped list of tuples. Like this:

``x = [1,2,3]  y = [4,5,6]  zipped = zip(x,y)  unzipped_x, unzipped_y = zip(*zipped)  unzipped_x      Out[30]: (1, 2, 3)  unzipped_y      Out[31]: (4, 5, 6)  ``

What on earth is going on? What is that magical asterisk doing? Where else can it be applied and what other amazing awesome things in Python are so mysterious and hard to google?

### Solution:1

The asterisk in Python is documented in the Python tutorial, under Unpacking Argument Lists.

### Solution:2

The asterisk performs `apply` (as it's known in Lisp and Scheme). Basically, it takes your list, and calls the function with that list's contents as arguments.

### Solution:3

It's also useful for multiple args:

``def foo(*args):    print args    foo(1, 2, 3) # (1, 2, 3)    # also legal  t = (1, 2, 3)  foo(*t) # (1, 2, 3)  ``

And, you can use double asterisk for keyword arguments and dictionaries:

``def foo(**kwargs):     print kwargs    foo(a=1, b=2) # {'a': 1, 'b': 2}    # also legal  d = {"a": 1, "b": 2}  foo(**d) # {'a': 1, 'b': 2}  ``

And of course, you can combine these:

``def foo(*args, **kwargs):     print args, kwargs    foo(1, 2, a=3, b=4) # (1, 2) {'a': 3, 'b': 4}  ``

Pretty neat and useful stuff.

### Solution:4

It doesn't always work:

``>>> x = []  >>> y = []  >>> zipped = zip(x, y)  >>> unzipped_x, unzipped_y = zip(*zipped)  Traceback (most recent call last):    File "<stdin>", line 1, in <module>  ValueError: need more than 0 values to unpack  ``

Oops! I think it needs a skull to scare it into working:

``>>> unzipped_x, unzipped_y = zip(*zipped) or ([], [])  >>> unzipped_x  []  >>> unzipped_y  []  ``

In python3 I think you need

``>>> unzipped_x, unzipped_y = tuple(zip(*zipped)) or ([], [])  ``

since zip now returns a generator function which is not False-y.

### Solution:5

I'm extremely new to Python so this just recently tripped me up, but it had to do more with how the example was presented and what was emphasized.

What gave me problems with understanding the zip example was the asymmetry in the handling of the zip call return value(s). That is, when zip is called the first time, the return value is assigned to a single variable, thereby creating a list reference (containing the created tuple list). In the second call, it's leveraging Python's ability to automatically unpack a list (or collection?) return value into multiple variable references, each reference being the individual tuple. If someone isn't familiar with how that works in Python, it makes it easier to get lost as to what's actually happening.

``>>> x = [1, 2, 3]  >>> y = "abc"  >>> zipped = zip(x, y)  >>> zipped  [(1, 'a'), (2, 'b'), (3, 'c')]  >>> z1, z2, z3 = zip(x, y)  >>> z1  (1, 'a')  >>> z2  (2, 'b')  >>> z3  (3, 'c')  >>> rezipped = zip(*zipped)  >>> rezipped  [(1, 2, 3), ('a', 'b', 'c')]  >>> rezipped2 = zip(z1, z2, z3)  >>> rezipped == rezipped2  True  ``

### Solution:6

``>>> def f(a2,a1):  ...  print a2, a1  ...   >>> d = {'a1': 111, 'a2': 222}  >>> f(**d)  222 111  ``